dictionary pop() function in python by R4R Team

- pop() in a dictionary slightly same as popitem() function, both are able to pop(delete) the item from the dictionary.
- popitem() function remove the top most item of the dictionary.
- while pop() function remove the specified item from the dictionary.

Syntax-

dict.pop(key)

Example-

dictionary is d={1:"one",2:"two",3:"three"}
d.pop(1)
will give {2:"two",3:"three"}


program-

d={1:"one",2:"two",3:"Three",4:"Four"}
print(d)

d.pop(1)
print(d)

d.pop(2)
print(d)

d.pop(3)
print(d)

d.pop(4)
print(d)

output-

{1: 'one', 2: 'two', 3: 'Three', 4: 'Four'}
{2: 'two', 3: 'Three', 4: 'Four'}
{3: 'Three', 4: 'Four'}
{4: 'Four'}
{}

-In this program, initially we have a dictionary {1:"one",2:"two",3:"three"} then we pop the items from the dictionary with the help of the keys like d.pop(1), here 1 is a key so this function remove the content of 1.
-If we do not give any argument to pop() function like-


program-

d={1:"one",2:"two",3:"Three",4:"Four"}
print(d)
d.pop()
print(d)

output-

d.pop()
TypeError: pop expected at least 1 arguments, got 0