Find maximum in doubly linked list by R4R Team

traverse() function are used to get all data from the doubly linked list.
maximum() function are used to find the maximum element in the doubly linked list.

program-

#include< stdio.h>
#include< conio.h>
#include< alloc.h>
struct node{
struct node *pre;
struct node *next;
int data;
};
struct node *first=NULL,*last=NULL;

void maximum()
{
struct node *ptr=first;
int max=ptr->data;
while(ptr!=NULL)
{
if(ptr->data>max)
max=ptr->data;
ptr=ptr->next;
}
printf("nMaximum is %d",max);
}

void traverse()
{
struct node *ptr=first;
while(ptr!=NULL){
printf("%d ",ptr->data);
ptr=ptr->next;
}
}

void main()
{
struct node *cpt,*ptr;
char ch;
clrscr();
first=(struct node*)malloc(sizeof(struct node));
printf("Enter first element in Linklist\n");
scanf("%d",&first->data);
first->pre=NULL;
ptr=first;
do
{
cpt=(struct node*)malloc(sizeof(struct node));
printf("Enter another data\n");
scanf("%d",&cpt->data);
ptr->next=cpt;
cpt->pre=ptr;
ptr=ptr->next;
printf("Continue(y/n) ?");
ch=getch();
}while(ch=='y');
ptr->next=NULL;
last=ptr;
printf("nDoubly Linked-list is:\n");
traverse();
maximum();
getch();
}


output-

Enter first element in Linklist
4
Enter another data
5
Continue(y/n)?
Enter another data
1
Continue(y/n)?
Enter another data
9
Continue(y/n)?
Enter another data
0
Continue(y/n)?
Doubly Linked-List is
4 5 1 9 0
Maximum is 9




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